已知函数f(x)=根号3sinxcosx-cos^2x-1⼀2 q求f(x)最小值和最小正周期

已知函数f(x)=根号3sinxcosx-cos^2x-1/2 q求f(x)最小值和最小正周期
2025-12-17 17:06:49
推荐回答(2个)
回答1:

f(x) = √3sinxcosx-cos^2x-1/2
= √3/2sin2x-(cos2x + 1)/2 - 1/2
= √3/2sin2x-1/2cos2x - 1
= sin2xcosπ/6-cos2xsinπ/6 - 1
= sin(2x-π/6) - 1
sin(2x-π/6) ≥-1
f(x) = sin(2x-π/6) - 1 ≥ -2,最小值-2
2π/2 = π,最小正周期π

回答2:

π